function [x,t,u] = Mixed_EA(L,N,T,K,c1,c2,f,u0,D)
% ----  Solution of heat equation ----
%   u_t - u_xx = f in the interval [-L,L] (doesn't matter if we change it)
%   Dirichlet BC
%  
% -----------------------------------------------
% Sintassi:
%   [x,t,u]=calore_template(L,N,T,K,c1,c2,fun,u0)
%
% Input:
%   L Half of the width (-L,L) 
%	N number of intervals in (-L,L)
%   T max time (0,T)
%	K number of intervals in (0,T)
%   c1 Dirichlet BC in x=-L
%   c2 Dirichlet BC in x=L
%   f force function
%   u0 initial condition in t=0
%
% Output:
%   x vector of the spatial nodes
%   t vector of the time nodes
%   u numeric solution of the problem

% discretisation step in time and space
h=L/N; %space
tau=T/K; %time
% Initialization of t
t=linspace(0,T,K+1)';
% initialization of x
x=linspace(0,L,N+1);

% Initialization of the matrix solution u
u=zeros(N+1,K+1);
% Intial conditions
u(:,1)=u0(x);

% BC Dirichlet
u(1,:)=c1(t);

% Creation of the matrix A
% We obtained this matrix using the Central Discretization method
e=ones(N-1,1);
A=spdiags([-e,2*e,-e],[-1,0,1],N-1,N-1)/(h^2);
%modify the matrix such that we can use the noimann condition to calculate
%the last node.
%In this case we want to use a second order decentralized approximation 
A(end,end-1)=-2/(h^2);
I=speye(N-1,N-1);

% Compute the solution
% What we are doing here is to compute the solution in the interval for
% each time k
for k=1:K
    % Assembly of the force
    F=f(x(2:end-1),t(k));
    % Correction of the force using the BC
    F(1)=F(1) + D*c1(t(k))/(h^2);
    F(end)=F(end) + 2*h*c2;
    % Solution using Eulero forward
    u(2:end-1,k+1) = ((I - D*tau*A)*u(2:end-1,k))' + tau*F;
    u(end,k+1)=u(end-2,k+1) + c2*2*h*D;
end